haskell

AI agents, Haskell, and the stubbornness of developers

Recently, I found an article about a member of the Haskell Foundation – who was moving his company away from Haskell. The company built a hardware product with Haskell, and they were moving away reluctantly.

I’m not going to repeat the whole thing here (you can read it yourself, but the TL;DR; is: the Haskell compiler and tooling ecosystem was too slow, and that became a bottleneck now that the LLM agent writing the code is so fast.

Now, let’s be clear: I don’t want to start a holy war about “static versus dynamic typing”, so I’m not going to do that. I’m not going to discuss if the merits of static typing are overrated or not, and I’m not going to discuss if dynamic languages are more or less flexible. This was discussed over and over again – and nobody knows the result. And for me, that in-determination is also a result.

What I am going to talk about is the stubbornness of software developers. It’s something that’s been bothering me for a couple of years now, and it still bothers me today. Looking at this article was no different.
(more…)

By Maurício Szabo, ago

Subtyping on functional languages

This is almost a new post on the Function SOLID series. It should be about the Liskov Substitution Princible, but before we talk about it it’s important to understand the concept of subtyping.

Subtyping in Dynamic languages like Clojure or in languages that do not have hierarchical typing like Haskell seems strange. But subtyping is not only a concept about object-oriented programming languages – it’s about restrictions, and the concept of variance. I’m going to try to explain both in this post

To begin with, we can say that a supertype is more generic than a subtype, but that’s not all. In truth, is all about properties that you can prove about a specific data. For example, if we use Clojure as a starting language you could say that the coll? is a property of maps and vectors, but vector? is a property that only applies to vectors. In practice, this means that coll? is a superclass of vector?.

(coll? []) ; => true
(coll? {}) ; => true

(vector? []) ; => true
(vector? {}) ; => false

(more…)

By Maurício Szabo, ago